Optimal. Leaf size=433 \[ \frac{2 \left (-a^2 b d^3 \left (11 c^2+5 d^2\right )+6 a^3 c d^4+6 a b^2 c d^4-b^3 \left (17 c^2 d^3+3 c^4 d+8 d^5\right )\right ) \sqrt{a+b \tan (e+f x)}}{3 f \left (a^2+b^2\right ) \left (c^2+d^2\right )^2 (b c-a d)^3 \sqrt{c+d \tan (e+f x)}}-\frac{2 d \left (a^2 d^2+b^2 \left (3 c^2+4 d^2\right )\right ) \sqrt{a+b \tan (e+f x)}}{3 f \left (a^2+b^2\right ) \left (c^2+d^2\right ) (b c-a d)^2 (c+d \tan (e+f x))^{3/2}}-\frac{2 b^2}{f \left (a^2+b^2\right ) (b c-a d) \sqrt{a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}-\frac{i \tanh ^{-1}\left (\frac{\sqrt{c-i d} \sqrt{a+b \tan (e+f x)}}{\sqrt{a-i b} \sqrt{c+d \tan (e+f x)}}\right )}{f (a-i b)^{3/2} (c-i d)^{5/2}}+\frac{i \tanh ^{-1}\left (\frac{\sqrt{c+i d} \sqrt{a+b \tan (e+f x)}}{\sqrt{a+i b} \sqrt{c+d \tan (e+f x)}}\right )}{f (a+i b)^{3/2} (c+i d)^{5/2}} \]
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Rubi [A] time = 1.95759, antiderivative size = 433, normalized size of antiderivative = 1., number of steps used = 10, number of rules used = 6, integrand size = 29, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.207, Rules used = {3569, 3649, 3616, 3615, 93, 208} \[ \frac{2 \left (-a^2 b d^3 \left (11 c^2+5 d^2\right )+6 a^3 c d^4+6 a b^2 c d^4-b^3 \left (17 c^2 d^3+3 c^4 d+8 d^5\right )\right ) \sqrt{a+b \tan (e+f x)}}{3 f \left (a^2+b^2\right ) \left (c^2+d^2\right )^2 (b c-a d)^3 \sqrt{c+d \tan (e+f x)}}-\frac{2 d \left (a^2 d^2+b^2 \left (3 c^2+4 d^2\right )\right ) \sqrt{a+b \tan (e+f x)}}{3 f \left (a^2+b^2\right ) \left (c^2+d^2\right ) (b c-a d)^2 (c+d \tan (e+f x))^{3/2}}-\frac{2 b^2}{f \left (a^2+b^2\right ) (b c-a d) \sqrt{a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}-\frac{i \tanh ^{-1}\left (\frac{\sqrt{c-i d} \sqrt{a+b \tan (e+f x)}}{\sqrt{a-i b} \sqrt{c+d \tan (e+f x)}}\right )}{f (a-i b)^{3/2} (c-i d)^{5/2}}+\frac{i \tanh ^{-1}\left (\frac{\sqrt{c+i d} \sqrt{a+b \tan (e+f x)}}{\sqrt{a+i b} \sqrt{c+d \tan (e+f x)}}\right )}{f (a+i b)^{3/2} (c+i d)^{5/2}} \]
Antiderivative was successfully verified.
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Rule 3569
Rule 3649
Rule 3616
Rule 3615
Rule 93
Rule 208
Rubi steps
\begin{align*} \int \frac{1}{(a+b \tan (e+f x))^{3/2} (c+d \tan (e+f x))^{5/2}} \, dx &=-\frac{2 b^2}{\left (a^2+b^2\right ) (b c-a d) f \sqrt{a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}-\frac{2 \int \frac{\frac{1}{2} \left (-a b c+a^2 d+4 b^2 d\right )+\frac{1}{2} b (b c-a d) \tan (e+f x)+2 b^2 d \tan ^2(e+f x)}{\sqrt{a+b \tan (e+f x)} (c+d \tan (e+f x))^{5/2}} \, dx}{\left (a^2+b^2\right ) (b c-a d)}\\ &=-\frac{2 b^2}{\left (a^2+b^2\right ) (b c-a d) f \sqrt{a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}-\frac{2 d \left (a^2 d^2+b^2 \left (3 c^2+4 d^2\right )\right ) \sqrt{a+b \tan (e+f x)}}{3 \left (a^2+b^2\right ) (b c-a d)^2 \left (c^2+d^2\right ) f (c+d \tan (e+f x))^{3/2}}-\frac{4 \int \frac{\frac{1}{4} \left (-3 a^3 c d^2-3 a b^2 c \left (c^2+2 d^2\right )+a^2 b d \left (6 c^2+5 d^2\right )+b^3 d \left (9 c^2+8 d^2\right )\right )+\frac{3}{4} (b c-a d)^2 (b c+a d) \tan (e+f x)+\frac{1}{2} b \left (a^2 d^3+b^2 \left (3 c^2 d+4 d^3\right )\right ) \tan ^2(e+f x)}{\sqrt{a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}} \, dx}{3 \left (a^2+b^2\right ) (b c-a d)^2 \left (c^2+d^2\right )}\\ &=-\frac{2 b^2}{\left (a^2+b^2\right ) (b c-a d) f \sqrt{a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}-\frac{2 d \left (a^2 d^2+b^2 \left (3 c^2+4 d^2\right )\right ) \sqrt{a+b \tan (e+f x)}}{3 \left (a^2+b^2\right ) (b c-a d)^2 \left (c^2+d^2\right ) f (c+d \tan (e+f x))^{3/2}}+\frac{2 \left (6 a^3 c d^4+6 a b^2 c d^4-a^2 b d^3 \left (11 c^2+5 d^2\right )-b^3 \left (3 c^4 d+17 c^2 d^3+8 d^5\right )\right ) \sqrt{a+b \tan (e+f x)}}{3 \left (a^2+b^2\right ) (b c-a d)^3 \left (c^2+d^2\right )^2 f \sqrt{c+d \tan (e+f x)}}-\frac{8 \int \frac{\frac{3}{8} (b c-a d)^3 \left (2 b c d-a \left (c^2-d^2\right )\right )+\frac{3}{8} (b c-a d)^3 \left (2 a c d+b \left (c^2-d^2\right )\right ) \tan (e+f x)}{\sqrt{a+b \tan (e+f x)} \sqrt{c+d \tan (e+f x)}} \, dx}{3 \left (a^2+b^2\right ) (b c-a d)^3 \left (c^2+d^2\right )^2}\\ &=-\frac{2 b^2}{\left (a^2+b^2\right ) (b c-a d) f \sqrt{a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}-\frac{2 d \left (a^2 d^2+b^2 \left (3 c^2+4 d^2\right )\right ) \sqrt{a+b \tan (e+f x)}}{3 \left (a^2+b^2\right ) (b c-a d)^2 \left (c^2+d^2\right ) f (c+d \tan (e+f x))^{3/2}}+\frac{2 \left (6 a^3 c d^4+6 a b^2 c d^4-a^2 b d^3 \left (11 c^2+5 d^2\right )-b^3 \left (3 c^4 d+17 c^2 d^3+8 d^5\right )\right ) \sqrt{a+b \tan (e+f x)}}{3 \left (a^2+b^2\right ) (b c-a d)^3 \left (c^2+d^2\right )^2 f \sqrt{c+d \tan (e+f x)}}+\frac{\int \frac{1+i \tan (e+f x)}{\sqrt{a+b \tan (e+f x)} \sqrt{c+d \tan (e+f x)}} \, dx}{2 (a-i b) (c-i d)^2}+\frac{\int \frac{1-i \tan (e+f x)}{\sqrt{a+b \tan (e+f x)} \sqrt{c+d \tan (e+f x)}} \, dx}{2 (a+i b) (c+i d)^2}\\ &=-\frac{2 b^2}{\left (a^2+b^2\right ) (b c-a d) f \sqrt{a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}-\frac{2 d \left (a^2 d^2+b^2 \left (3 c^2+4 d^2\right )\right ) \sqrt{a+b \tan (e+f x)}}{3 \left (a^2+b^2\right ) (b c-a d)^2 \left (c^2+d^2\right ) f (c+d \tan (e+f x))^{3/2}}+\frac{2 \left (6 a^3 c d^4+6 a b^2 c d^4-a^2 b d^3 \left (11 c^2+5 d^2\right )-b^3 \left (3 c^4 d+17 c^2 d^3+8 d^5\right )\right ) \sqrt{a+b \tan (e+f x)}}{3 \left (a^2+b^2\right ) (b c-a d)^3 \left (c^2+d^2\right )^2 f \sqrt{c+d \tan (e+f x)}}+\frac{\operatorname{Subst}\left (\int \frac{1}{(1-i x) \sqrt{a+b x} \sqrt{c+d x}} \, dx,x,\tan (e+f x)\right )}{2 (a-i b) (c-i d)^2 f}+\frac{\operatorname{Subst}\left (\int \frac{1}{(1+i x) \sqrt{a+b x} \sqrt{c+d x}} \, dx,x,\tan (e+f x)\right )}{2 (a+i b) (c+i d)^2 f}\\ &=-\frac{2 b^2}{\left (a^2+b^2\right ) (b c-a d) f \sqrt{a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}-\frac{2 d \left (a^2 d^2+b^2 \left (3 c^2+4 d^2\right )\right ) \sqrt{a+b \tan (e+f x)}}{3 \left (a^2+b^2\right ) (b c-a d)^2 \left (c^2+d^2\right ) f (c+d \tan (e+f x))^{3/2}}+\frac{2 \left (6 a^3 c d^4+6 a b^2 c d^4-a^2 b d^3 \left (11 c^2+5 d^2\right )-b^3 \left (3 c^4 d+17 c^2 d^3+8 d^5\right )\right ) \sqrt{a+b \tan (e+f x)}}{3 \left (a^2+b^2\right ) (b c-a d)^3 \left (c^2+d^2\right )^2 f \sqrt{c+d \tan (e+f x)}}+\frac{\operatorname{Subst}\left (\int \frac{1}{i a+b-(i c+d) x^2} \, dx,x,\frac{\sqrt{a+b \tan (e+f x)}}{\sqrt{c+d \tan (e+f x)}}\right )}{(a-i b) (c-i d)^2 f}+\frac{\operatorname{Subst}\left (\int \frac{1}{-i a+b-(-i c+d) x^2} \, dx,x,\frac{\sqrt{a+b \tan (e+f x)}}{\sqrt{c+d \tan (e+f x)}}\right )}{(a+i b) (c+i d)^2 f}\\ &=-\frac{i \tanh ^{-1}\left (\frac{\sqrt{c-i d} \sqrt{a+b \tan (e+f x)}}{\sqrt{a-i b} \sqrt{c+d \tan (e+f x)}}\right )}{(a-i b)^{3/2} (c-i d)^{5/2} f}+\frac{i \tanh ^{-1}\left (\frac{\sqrt{c+i d} \sqrt{a+b \tan (e+f x)}}{\sqrt{a+i b} \sqrt{c+d \tan (e+f x)}}\right )}{(a+i b)^{3/2} (c+i d)^{5/2} f}-\frac{2 b^2}{\left (a^2+b^2\right ) (b c-a d) f \sqrt{a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}-\frac{2 d \left (a^2 d^2+b^2 \left (3 c^2+4 d^2\right )\right ) \sqrt{a+b \tan (e+f x)}}{3 \left (a^2+b^2\right ) (b c-a d)^2 \left (c^2+d^2\right ) f (c+d \tan (e+f x))^{3/2}}+\frac{2 \left (6 a^3 c d^4+6 a b^2 c d^4-a^2 b d^3 \left (11 c^2+5 d^2\right )-b^3 \left (3 c^4 d+17 c^2 d^3+8 d^5\right )\right ) \sqrt{a+b \tan (e+f x)}}{3 \left (a^2+b^2\right ) (b c-a d)^3 \left (c^2+d^2\right )^2 f \sqrt{c+d \tan (e+f x)}}\\ \end{align*}
Mathematica [A] time = 6.43446, size = 610, normalized size = 1.41 \[ -\frac{2 b^2}{f \left (a^2+b^2\right ) (b c-a d) \sqrt{a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}-\frac{2 \left (-\frac{2 \left (\frac{1}{2} d^2 \left (a^2 d-a b c+4 b^2 d\right )-c \left (\frac{1}{2} b d (b c-a d)-2 b^2 c d\right )\right ) \sqrt{a+b \tan (e+f x)}}{3 f \left (c^2+d^2\right ) (a d-b c) (c+d \tan (e+f x))^{3/2}}-\frac{2 \left (-\frac{2 \left (\frac{1}{4} d^2 \left (a^2 b d \left (6 c^2+5 d^2\right )-3 a^3 c d^2-3 a b^2 c \left (c^2+2 d^2\right )+b^3 d \left (9 c^2+8 d^2\right )\right )-c \left (\frac{3}{4} d (b c-a d)^2 (a d+b c)-\frac{1}{2} b c \left (a^2 d^3+b^2 \left (3 c^2 d+4 d^3\right )\right )\right )\right ) \sqrt{a+b \tan (e+f x)}}{f \left (c^2+d^2\right ) (a d-b c) \sqrt{c+d \tan (e+f x)}}+\frac{3 (b c-a d)^3 \left (\frac{(b+i a) (c-i d)^2 \tan ^{-1}\left (\frac{\sqrt{-c-i d} \sqrt{a+b \tan (e+f x)}}{\sqrt{a+i b} \sqrt{c+d \tan (e+f x)}}\right )}{\sqrt{a+i b} \sqrt{-c-i d}}+\frac{(-b+i a) (c+i d)^2 \tan ^{-1}\left (\frac{\sqrt{c-i d} \sqrt{a+b \tan (e+f x)}}{\sqrt{-a+i b} \sqrt{c+d \tan (e+f x)}}\right )}{\sqrt{-a+i b} \sqrt{c-i d}}\right )}{4 f \left (c^2+d^2\right ) (a d-b c)}\right )}{3 \left (c^2+d^2\right ) (a d-b c)}\right )}{\left (a^2+b^2\right ) (b c-a d)} \]
Antiderivative was successfully verified.
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Maple [F] time = 180., size = 0, normalized size = 0. \begin{align*} \int{ \left ( a+b\tan \left ( fx+e \right ) \right ) ^{-{\frac{3}{2}}} \left ( c+d\tan \left ( fx+e \right ) \right ) ^{-{\frac{5}{2}}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{{\left (b \tan \left (f x + e\right ) + a\right )}^{\frac{3}{2}}{\left (d \tan \left (f x + e\right ) + c\right )}^{\frac{5}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: TypeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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